2x^2+27x+70=

Solution for 2x^2+27x+70= equation:

2x^2+27x+70=

We move all terms to the left:

2x^2+27x+70-()=0

We add all the numbers together, and all the variables

2x^2+27x=0

a = 2; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·2·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*2}=\frac{-54}{4}
=-13+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*2}=\frac{0}{4}
=0
$